the slap of the line passing through points ( x1, y1_ and (x2, y2) is found using the formula Y2- Y1/X2- X1
the line passing through points (1, 2) and (x, 5) is perpendicular to a line that has a slope of 1/3. what is the value of x?
10
-2
-4
0
First, find the slope of the line passing through points (1, 2) and (x, 5):
Slope = (5 - 2) / (x - 1)
Slope = 3 / (x - 1)
Since the line passing through (1, 2) and (x, 5) is perpendicular to the line with a slope of 1/3, the product of their slopes will be -1 (since the product of slopes of perpendicular lines is -1):
(3 / (x - 1)) * (1/3) = -1
1 / (x - 1) = -1
x - 1 = -1
x = 0
Therefore, the value of x is 0.