Polynomials
Solve the following in box method:
3 to the second power times 16x-18=-6
First, let's multiply \(3^2\) which is 9.
So, \(9(16x - 18) = -6\)
Next, use the box method to expand \(9(16x - 18)\):
\[
\begin{array}{|c|c|c|}
\hline
9 & 16x & -18 \\
\hline
& 144x & -162 \\
\hline
\end{array}
\]
Now, simplify the expression:
\(144x - 162 = -6\)
Finally, solve for x:
\(144x = -6 + 162\)
\(144x = 156\)
\(x = \frac{156}{144}\)
\(x = \frac{13}{12}\)