A dime is approximately 1.35 x 10^−1cm thick. The thickness of a dollar bill is approximately 1.2 x10^−2
How many times greater is the thickness of a dime than the thickness of a dollar bill?
To find how many times greater the thickness of a dime is than the thickness of a dollar bill, we need to divide the thickness of the dime by the thickness of the dollar bill:
(1.35 x 10^−1) / (1.2 x 10^−2)
Now we can simplify this division by dividing the numbers and subtracting the exponents:
(1.35 / 1.2) x 10^(−1 - −2)
= 1.125 x 10^(1)
= 11.25
Therefore, the thickness of a dime is 11.25 times greater than the thickness of a dollar bill.