if i have 17 liters of a gas at a temperature of 67 degrees C and a pressure of 88.89 atm, what will be the pressure of the gas if the temperature of the gas is raised to 94 degrees C and the volume of the gas is kept at 17 liters?
To solve this problem, we can use the combined gas law equation, which states:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure of the gas
V1 = initial volume of the gas
T1 = initial temperature of the gas
P2 = final pressure of the gas
V2 = final volume of the gas
T2 = final temperature of the gas
Plugging in the values given:
P1 = 88.89 atm
V1 = 17 liters
T1 = 67 degrees C
V2 = 17 liters
T2 = 94 degrees C
(88.89 * 17) / 67 = (P2 * 17) / 94
1513.13 / 67 = P2
P2 = 22.6 atm
Therefore, the pressure of the gas when the temperature is raised to 94 degrees C and the volume is kept at 17 liters will be approximately 22.6 atm.