i have to find the derivative (first) of
y= tan^2 (3x-π)
^that is (3x- pi)
Use the power rule
y= a^u
y'= u a^(u-1) da/dx
y'= 2tan( ) d tan(3x-PI)/dx
= 2 tan ( )* sec^2( ) * 3
y= tan^2 (3x-π)
^that is (3x- pi)
y= a^u
y'= u a^(u-1) da/dx
y'= 2tan( ) d tan(3x-PI)/dx
= 2 tan ( )* sec^2( ) * 3