Your employer is offering free tickets for two baseball games they play 53 home games and 8 of them are against the snakes the tickets are randomly given out what is the probability that both are games against the snakes? Write as a fraction
The probability of the first game being against the snakes is 8/53, since there are 8 games against the snakes out of a total of 53 games.
After the first game is selected as against the snakes, there are now 7 games against the snakes left out of 52 total games for the second game. Therefore, the probability of the second game being against the snakes is 7/52.
To find the probability that both games are against the snakes, we multiply the probabilities of the two events: (8/53) * (7/52) = 56/2756 = 14/689.
Therefore, the probability that both games are against the snakes is 14/689.