The 10th term of an arithmetic progress is 68 and the common difference is -3,find the 15th term of the sequence
To find the 15th term of the sequence, we first need to find the first term of the sequence.
Let the first term of the sequence be denoted as 'a'. We are given that the 10th term is 68 and the common difference is -3. We know that the formula for the nth term of an arithmetic progression is given by:
An = a + (n-1)d
where An is the nth term, a is the first term, n is the term number, and d is the common difference.
Substitute the values we know:
68 = a + (10-1)(-3)
68 = a + 9(-3)
68 = a - 27
a = 68 + 27
a = 95
Now that we have found the first term (95), we can find the 15th term using the same formula:
A15 = 95 + (15-1)(-3)
A15 = 95 + 14(-3)
A15 = 95 - 42
A15 = 53
Therefore, the 15th term of the sequence is 53.