Find the sum of the twelve term of the sequence 2,5,8,11.....
First, let's find the common difference of the sequence:
5 - 2 = 3
8 - 5 = 3
11 - 8 = 3
Since the common difference is 3, we can find the 12th term of the sequence:
a12 = a1 + (n-1)d
a12 = 2 + (12-1)3
a12 = 2 + 33
a12 = 35
Now, let's find the sum of the first 12 terms of the sequence using the formula:
Sn = n/2 * (a1 + an)
Sn = 12/2 * (2 + 35)
Sn = 6 * 37
Sn = 222
Therefore, the sum of the first twelve terms of the sequence 2, 5, 8, 11.... is 222.