olve the system of equations.
2x+8y=8
2x−4y=−16
To solve this system of equations, we will use the method of elimination.
1) First, we will multiply the second equation by 2 to make the coefficients of x the same:
2(2x - 4y) = 2(-16)
4x - 8y = -32
2) Now, we have the system of equations:
2x + 8y = 8
4x - 8y = -32
3) Add the two equations together:
6x = -24
4) Divide by 6 to solve for x:
x = -4
5) Substitute x = -4 back into the first equation:
2(-4) + 8y = 8
-8 + 8y = 8
8y = 16
y = 2
6) The solution to the system of equations is x = -4 and y = 2.