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An illustration shows a polygon where the top, right, and bottom sides are perpendicular to each other. A smaller rectangular piece is missing from the center of the left side of the polygon inward. The dimensions are as follows: the top side is 6, the right side is 8, and the bottom side is 6. The left side is divided into three parts. It shows a vertical width of 2 from the top
Solve the following problem using what you know about composite figures. What is the area of the figure?(1 point)
Responses
24 square units
24 square units
36 square units
36 square units
48 square units
48 square units
30 square units
To find the area of the figure, we need to break it down into smaller shapes and then calculate the total area.
First, we have a rectangle with dimensions 6 x 6, which has an area of 6 x 6 = 36 square units.
Next, we have a smaller rectangle within this shape with dimensions 6 x 2, which has an area of 6 x 2 = 12 square units.
Then, we subtract the area of the smaller rectangle from the larger rectangle to find the area of the figure.
36 - 12 = 24 square units.
Therefore, the correct answer is 24 square units.
i thought the shape had a third parrt
Apologies for the oversight. Let's calculate the area again considering the missing piece on the left side which divides the left side into three parts.
The left side of the polygon is 6 units long and is divided into three parts of equal width. This means each part is 2 units wide.
The area of the smaller rectangle missing from the left side can be found by multiplying 2 (width) by the height of the larger rectangle, which is 6 units.
Therefore, the area of the missing piece is 2 x 6 = 12 square units.
Now, we calculate the area of the figure by subtracting the area of the missing piece from the total area of the rectangle.
36 (total area of the rectangle) - 12 (area of the missing piece) = 24 square units.
Therefore, the correct answer is 24 square units.