A sample of methane gas collected at a pressure of 230 mm Hg and a temperature of 295 K has a mass of 18.0 grams. The volume of the sample is
L.
To find the volume of the sample, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure (230 mm Hg)
V = volume
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (295 K)
First, we need to calculate the number of moles of methane in the sample using the mass given (18.0 grams) and the molar mass of methane (16.04 g/mol).
n = mass / molar mass
n = 18.0 g / 16.04 g/mol
n = 1.12 mol
Now, we can rearrange the ideal gas law equation to solve for volume:
V = nRT / P
V = (1.12 mol)(0.0821 L.atm/mol.K)(295 K) / 230 mm Hg
V = (1.12)(0.0821)(295) / 230
V = 0.325 L
Therefore, the volume of the methane gas sample is 0.325 L.