A sample of methane gas at a pressure of 0.730 atm and a temperature of 25.9 °C, occupies a volume of 733 mL. If the gas is allowed to expand at constant temperature until its pressure is 0.345 atm, the volume of the gas sample will be
mL.
Using the combined gas law formula, we can determine the final volume of the gas sample:
P1V1/T1 = P2V2/T2
Where:
P1 = initial pressure = 0.730 atm
V1 = initial volume = 733 mL
T1 = initial temperature = 25.9 °C = 298.9 K
P2 = final pressure = 0.345 atm
V2 = final volume = unknown
T2 = final temperature = 25.9 °C = 298.9 K
Plugging in the values, we get:
(0.730 atm)(733 mL)/(298.9 K) = (0.345 atm)(V2)/(298.9 K)
Solving for V2:
V2 = (0.730 atm)(733 mL)/(0.345 atm)
V2 = 1553.91 mL
Therefore, the volume of the gas sample when the pressure is 0.345 atm is 1553.91 mL.