The maximum value of the emf generated in a 32-turn coil is 260V. The coil with dimensions of 360mm by 200mm is rotated about an axis through centre and parallel to the coil sides. Calculate the following if the field has a uniform magnetic flux density of 0,86T:
A) The speed at which the coil is rotated
To calculate the speed at which the coil is rotated, we can use the formula for emf generated in a coil:
emf = N * B * A * w
where emf is the electromagnetic force generated (260V), N is the number of turns in the coil (32), B is the magnetic flux density (0.86T), A is the area of the coil (360mm * 200mm = 0.36m * 0.20m = 0.072m^2), and w is the angular velocity of the coil.
Rearranging the formula to solve for w:
w = emf / (N * B * A)
w = 260V / (32 * 0.86T * 0.072m^2)
w = 5.46875 rad/s
Therefore, the speed at which the coil is rotated is 5.46875 rad/s.