John has to make all three free throws to win the game. Assume each free-throw is an independent event and that the pressure of the situation has no impact on him. If John is a 55% free-throw shooter, what is the percent chance that John makes all three free throws.
The probability of John making one free throw is 0.55, and the probability of him missing one free throw is 0.45. Since each free throw is an independent event, we can calculate the probability of him making all three free throws by multiplying the probabilities of him making each individual free throw:
0.55 * 0.55 * 0.55 = 0.166375
Therefore, the percent chance that John makes all three free throws is approximately 16.64%.