Courtney is constructing quadrilateral EFGH, where EF = 6 cm, FG = 2 cm,

Question

Courtney is constructing quadrilateral EFGH, where EF = 6 cm, FG = 2 cm,

EH = 5 cm, <HEF = 60°
, and LEFG = 140°
•. Courtney starts by drawing line segment
EF = 6 cm, as shown here. If she wants to locate point H next, what should Courtney do?

Answer 1

To locate point H, Courtney should draw a line segment GH of length 2 cm from point G at an angle of 140° counterclockwise from EF, which is line segment GH. This will form the quadrilateral EFGH with EF = 6 cm, FG = 2 cm, and EH = 5 cm.