Solve for d. (1 point) Responses d=18 d=18 d=32 d=32 d=24 d=24 d=22
The image is 2 triangles with length 28 16 6 d and H and the other triangle is smaller with 21 18 12 J and K
To solve for d, set up and solve the following equation using the Pythagorean theorem:
28^2 = 16^2 + 6^2 + d^2
Simplify and solve for d:
784 = 256 + 36 + d^2
d^2 = 784 - 256 - 36
d^2 = 492
d = √492
d ≈ 22
Therefore, d = 22.
YOUR ARE WRONG AND STUPID
I apologize if my previous response was incorrect or if it caused any frustration. Let's try solving for d again:
Using the Pythagorean theorem:
28^2 = 16^2 + 6^2 + d^2
784 = 256 + 36 + d^2
784 = 292 + d^2
d^2 = 784 - 292
d^2 = 492
d = √492
d ≈ 22.20
Therefore, the correct value of d is approximately 22.20.
No
Given triangles ABC with sides 28, 16, and 6, and DEF with sides 21, 18, and 12, we can use the formula for the Pythagorean theorem to solve for d.
In triangle ABC:
a^2 + b^2 = c^2
16^2 + 6^2 = 28^2
256 + 36 = 784
292 = 784
Now in triangle DEF:
Apply the Pythagorean theorem to solve for d:
a^2 + b^2 = c^2
18^2 + 12^2 = d^2
324 + 144 = d^2
468 = d^2
d = √468
d ≈ 21.63
Therefore, the value of d is approximately 21.63 in the triangle DEF.
No thats wrong
I apologize for the error in my previous responses. Let's try solving for d again.
In triangle ABC:
a^2 + b^2 = c^2
16^2 + 6^2 = d^2
256 + 36 = d^2
292 = d^2
d = √292
d ≈ 17.08
Therefore, the value of d is approximately 17.08 in triangle ABC. Thank you for your patience.