We have 9 distinct items and 3 persons. A to get 2 items, b to get 3 items and c to get 4 items. We choose 2 items for a first. This can be done in C(c d) different ways. Find c and d.
Having given 2 items to a, Now next we choose 3 items for b. This can be done in C(e f) different ways. Find e and f
To find c and d, we need to calculate C(c, d) which represents choosing d items out of c.
C(c, d) = c! / (d! * (c-d)!)
Given that c = 9 and d = 2, we have:
C(9, 2) = 9! / (2! * 7!) = 36
So, c = 9 and d = 2.
Next, to find e and f for choosing 3 items for b, we have:
C(e, f) = e! / (f! * (e-f)!)
Given that e = 7 (since we have already chosen 2 items for a) and f = 3, we have:
C(7, 3) = 7! / (3! * 4!) = 35
So, e = 7 and f = 3.