A measuring cylinder contains water that is filled to the 50cm^3 marking. An irregularly-shaped object is placed into this water. The water is now at the 77cm^3 marking. What is the volume of the irregularly-shaped object?
To find the volume of the irregularly-shaped object, we need to calculate the difference in water levels before and after the object is added.
The difference in water levels is 77cm^3 - 50cm^3 = 27cm^3.
Therefore, the volume of the irregularly-shaped object is 27cm^3.
An object has a mass of 94g, and a volume of 120 cm3, was is its density
To calculate the density of the object, we use the formula:
Density = mass / volume
Given:
Mass = 94g
Volume = 120 cm^3
Density = 94g / 120 cm^3
Density = 0.783 g/cm^3
Therefore, the density of the object is 0.783 g/cm^3.
Calculate the energy needed to change the state of 0.35 kg of water from liquid to gas, at constant temperature. The specific latent heat of vaporisation for water: 2.26 MJ/kg
To calculate the energy needed to change the state of water from liquid to gas, we use the formula:
Energy = mass x specific latent heat of vaporization
Given:
Mass = 0.35 kg
Specific latent heat of vaporization for water = 2.26 MJ/kg
Energy = 0.35 kg x 2.26 MJ/kg
Energy = 0.35 kg x 2.26 x 10^6 J/kg (converting MJ to J)
Energy = 791,000 J
Therefore, the energy needed to change the state of 0.35 kg of water from liquid to gas at constant temperature is 791,000 Joules.
How much water has been heated if it took 20000J to heat it by 80C? (Specific Heat Capacity of water is 4200 J/kgC)
To calculate the mass of water heated, we can use the formula:
\[ \text{Energy} = \text{Mass} \times \text{Specific Heat Capacity} \times \text{Change in Temperature} \]
Given:
- Energy = 20000 J
- Change in Temperature = 80°C
- Specific Heat Capacity of water = 4200 J/kg°C
Substitute these values into the formula:
\[ 20000 = \text{Mass} \times 4200 \times 80 \]
\[ 20000 = \text{Mass} \times 336000 \]
\[ \text{Mass} = \frac{20000}{336000} \]
\[ \text{Mass} \approx 0.0595 \, \text{kg} \]
Therefore, approximately 0.0595 kg of water has been heated.
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To calculate the mass of water that has been heated, we can use the formula:
Energy = Mass x Specific Heat Capacity x Change in Temperature
Given:
Energy = 20000 J
Change in Temperature = 80°C
Specific Heat Capacity of water = 4200 J/kg°C
Substitute these values into the formula:
20000 = Mass x 4200 x 80
Solving for Mass:
Mass = 20000 / (4200 x 80)
Mass ≈ 0.0595 kg
Therefore, approximately 0.0595 kg of water has been heated.