if a bullet starting from rest leaves the muzzle of a rifle with a speed of 600m/s and the barrel of the rifle is 0.90m long what is the acceleration of the bullet while in the barrel
To find the acceleration of the bullet while in the barrel, we can use the following kinematic equation:
v^2 = u^2 + 2as
where:
v = final velocity of the bullet (600 m/s)
u = initial velocity of the bullet (0 m/s, since it starts from rest)
a = acceleration of the bullet
s = distance traveled in the barrel (0.90 m)
Plugging in the values, we get:
600^2 = 0^2 + 2 * a * 0.90
a = (600^2) / (2 * 0.90)
a = 20000 m/s^2
Therefore, the acceleration of the bullet while in the barrel is 20000 m/s^2.