c. Determine the value of the enthalpy change, AH xn, for the following reaction using the information below.
→ 2 Al,03 (8) + 3 Mn (s)
2 Al + 3/2020 → AL,03 (
Mn( + 026 → MnO2 ()
ДН = -1676 kJ
ДН = -520.0 kJ
To determine the enthalpy change for the reaction, we first need to balance the given equations:
2 Al + 3/2 O2 → Al2O3
4 Mn + 3 O2 → 2 Mn2O3
Next, we add the balanced equations together to get the overall reaction:
2 Al + 3 Mn -> Al2O3 + 2 Mn2O3
Now we need to calculate the enthalpy change for the overall reaction. We can do this by adding the enthalpy changes of the individual reactions:
ΔH = Σ(ΔH of products) - Σ(ΔH of reactants)
ΔH = [2(-1676 kJ) + 2(-520.0 kJ)] - [0]
ΔH = -3352 kJ - 1040 kJ
ΔH = -4392 kJ
Therefore, the value of the enthalpy change, ΔHxn, for the reaction is -4392 kJ.