Using the balanced equation for the combustion of butane (C4H10), answer the following questions.
2C4H10 + 1302 - 8CO2 + 10H2O
Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
x10
How many grams of CO2 are formed from 8.5 mol of C4H10?
g CO2
From the balanced equation, we can see that 2 moles of C4H10 produce 8 moles of CO2.
Using the given amount of 8.5 mol of C4H10:
8.5 mol C4H10 x (8 mol CO2 / 2 mol C4H10) = 34 mol CO2
Next, we can convert moles of CO2 to grams:
34 mol CO2 x (44.01 g CO2 / 1 mol CO2) = 1494.34 g CO2
Therefore, 8.5 mol of C4H10 will produce 1494.34 g of CO2.