22.5 g of methanol (CH4O)
22.5 g CH4O =
mol CH4O
= 22.5 g / 32.04 g/mol (molar mass of methanol)
= 0.703 mol
Therefore, 22.5 g of methanol is equal to 0.703 mol.
22.5 g CH4O =
mol CH4O
= 0.703 mol
Therefore, 22.5 g of methanol is equal to 0.703 mol.