Marianne takes a screenshot of an original image on her computer. Then she shrinks the screenshot to create a thumbnail image. The original image is 800 pixels long. The thumbnail image is 160 pixels long and 120 pixels wide. How wide is the original image?
To maintain the proportion of the original image when creating a thumbnail, we need to shrink the original image by the same factor in both dimensions.
The original image is 800 pixels long and the thumbnail image is 160 pixels long, so the shrink factor is 160/800 = 0.2
To find the width of the original image, we need to multiply the width of the thumbnail image by the shrink factor:
120 pixels * 0.2 = 24 pixels
Therefore, the original image is 24 pixels wide.
wrong answer
I apologize for the mistake. Let's correct the calculation:
If the original image is shrunk proportionally so that the original image is 800 pixels long and the thumbnail image is 160 pixels long, we can find the ratio of the lengths of the original and thumbnail images:
800 pixels / 160 pixels = 5
This means that the original image is 5 times larger in length than the thumbnail image. Similarly, the original image is also 5 times longer in width than the thumbnail image, as the images have the same proportional dimensions.
Therefore, to find the width of the original image based on the width of the thumbnail image:
Width of original image = 120 pixels * 5 = 600 pixels
The original image is 600 pixels wide.