Propane
H2, molar mass = 2.016
C3H6 + H2 + C3Hg
Assuming 6.00 g of propene and 16.00 g of hydrogen are used, answer the following questions:
Part: 0 / 6
can be prepared by the reaction of propene
according to the following balanced equation:
C3H8, molar mass = 44.09
g
mol
g
mo1
C3H6, molar mass = 42.08
mol
with hydrogen
Part 2 of 6
moles of hydrogen =
Part 2 of 6
How many moles of hydrogen are used? Be sure your answer has the correct number of significant figures.
mol H2
To find the moles of hydrogen used, we first need to convert the given mass of hydrogen (16.00 g) to moles.
Molar mass of H2 = 2.016 g/mol
Moles of H2 = 16.00 g / 2.016 g/mol = 7.9375 mol
Therefore, the moles of hydrogen used are 7.94 mol.