hydrogen H2, molar mass = 2.016
C3H60 + H2 C3H7OH
Assuming 10.50 g of acetone and 20.50 g of hydrogen are used, answer the following questions:
Part: 0 / 6
Rubbing alcohol, or isopropanol ( C3H7OH, molar mass = 60.09
g
- according to the following balanced equation:
mol
, can be prepared by the reaction of acetone C3H6O, molar mass = 58.08 -
mol
Part 1 of 6
moles of acetone =
10
How many moles of acetone are used? Be sure your answer has the correct number of significant figures.
mol C3H6O
To find the moles of acetone used, we first need to convert the given mass of acetone (10.50 g) to moles using the molar mass of acetone:
10.50 g C3H6O x (1 mol C3H6O / 58.08 g C3H6O) = 0.1806 mol C3H6O
Therefore, the number of moles of acetone used is 0.1806 mol.