Using the balanced equation for the combustion of ethane (C2H6), answer the following questions.
Using the balanced equation for the combustion of ethane (C2H6), answer the following questions.
2C2H6 + 702 -+ 4CO2 + 6H20
Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
How many grams of CO2 are formed from 5.7 mol of C2H6?
g CO2
To find the grams of CO2 formed from 5.7 mol of C2H6, we first need to use the mole ratio from the balanced equation.
From the balanced equation, we see that 2 moles of C2H6 produce 4 moles of CO2. Therefore, the mole ratio is 4 moles of CO2 / 2 moles of C2H6 = 2 moles of CO2 / 1 mole of C2H6.
Now, calculate the number of moles of CO2 produced from 5.7 mol of C2H6 using the mole ratio:
5.7 mol C2H6 x (2 mol CO2 / 1 mol C2H6) = 11.4 mol CO2
Now, convert the moles of CO2 to grams:
11.4 mol CO2 x (44.01 g CO2 / 1 mol CO2) = 501.414 g CO2
Therefore, 501.414 grams of CO2 are formed from 5.7 mol of C2H6.