how many grams of CO2 are formed from 8.7 mol of C8H18
To solve this problem, we first need to determine the balanced chemical equation for the combustion of C8H18 (octane):
C8H18 + 12.5O2 → 8CO2 + 9H2O
From the balanced equation, we see that 1 mol of C8H18 produces 8 mol of CO2. Therefore, 8.7 mol of C8H18 will produce:
8.7 mol C8H18 * (8 mol CO2 / 1 mol C8H18) = 69.6 mol CO2
Next, we need to convert mol of CO2 to grams. The molar mass of CO2 is 44.01 g/mol. So,
69.6 mol CO2 * 44.01 g/mol CO2 = 3067.296 g CO2
Therefore, 8.7 mol of C8H18 will produce 3067.296 grams of CO2.