Using the figures from the story above: A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. Which of the following equations below provides the correct answer for the distance the balloon has fallen in 1 second? (Use the formula sheet that you were provided to help substitute the correct values in this question, Note that ^2 means the value prior is squared) (2 points) Responses v = (0m) + (0 m/s)(1.0 s) + 1 (9.8 m/s2)(1s)^2 = 9.8 m v = (0m) + (0 m/s)(1.0 s) + 1 (9.8 m/s2)(1s) ^ 2 = 9.8 m X = (0m) + (0 m/s)(1.0 s) + ½ (9.8 m/s2)(1s)^2 = 4.9 m X = (0m) + (0 m/s)(1.0 s) + ½ (9.8 m/s2)(1s) ^ 2 = 4.9 m v = (10m) + (0 m/s)(1.0 s) + ½ (9.8 m/s2)(1s)^2 = 14.9 m v = (10m) + (0 m/s)(1.0 s) + ½ (9.8 m/s2)(1s) ^ 2 = 14.9 m X = (0m) + (0 m/s)(1.0 s) + 10 (9.8 m/s2)(1s)^2 = 98 m
X = (0m) + (0 m/s)(1.0 s) + ½ (9.8 m/s2)(1s)^2 = 4.9 m
Therefore, the correct equation for the distance the balloon has fallen in 1 second is X = 4.9 m.