To show how to solve the equation, create two functions and find their intersection points. What two functions can be used to solve the following equation, and what is their solution set? x2+4x−1=2x+2 (1 point) Responses
f(x)=x2+4x−1 , g(x)=2x+2 , {−3,−4,1,4}
f(x)=x2+4x−1 , g(x)=2x+2 , {−3,1}
f(x)=x2+4x , g(x)=2x , {−3,1}
f(x)=x2+4x−1 , g(x)=2x+2 , {−1,3}
f(x)=x^2+4x−1 , g(x)=2x+2 , {−3,1}
To find the solution set, set the two functions equal to each other:
x^2+4x−1 = 2x+2
Rearrange the equation:
x^2 + 2x - 3 = 0
Factor the quadratic equation:
(x + 3)(x - 1) = 0
Set each factor equal to zero to find the roots:
x + 3 = 0 --> x = -3
x - 1 = 0 --> x = 1
Therefore, the solution set is {−3, 1}.