A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point) Responses 370 N 370 N 80 N 80 N 70 N 70 N 380 N
To find the net force acting on the boy, we need to subtract the force of drag and friction from the total force applied by the boy and his friend.
Total force applied by the boy and his friend = 300 N + 75 N = 375 N
Force of drag and friction = 5 N
Net force = Total force - Force of drag and friction
Net force = 375 N - 5 N
Net force = 370 N
Therefore, the magnitude of the net force acting on the boy is 370 N. So the correct answer is:
370 N