Find the value of n such that x^2 - 3x + n is a perfect square trinomial.
A perfect square trinomial can be factored as (x - a)^2, where a is a constant term.
In this case, we have x^2 - 3x + n. To make this a perfect square trinomial, we need to find the value of n such that it can be factored in the form (x - a)^2.
Expanding (x - a)^2, we get x^2 - 2ax + a^2. Comparing this with x^2 - 3x + n, we can see that -2a = -3 and a^2 = n.
From -2a = -3, we get a = 3/2.
Substitute a = 3/2 into a^2 = n, we get n = (3/2)^2 = 9/4.
Therefore, the value of n that makes x^2 - 3x + n a perfect square trinomial is 9/4.