The solvent dichloromethane (CH2CI2, molar mass=84.92 g/mol) can be prepared by the reaction of methane (CH4, molar mass=16.04 g/mol) with chlorine (CI2, molar mass= 70.89 g/mol) according to the following balanced equation: CH4+2CI2 CH2CI2+2HCI
Assuming 12.50 of methane and 22.50 of chlorine are used, answer the following questions:
How many moles of methane are used? Be sure your answer has the correct number of significant figures
To determine the number of moles of methane used, we need to divide the given mass of methane by its molar mass.
Mass of methane = 12.50 g
Molar mass of methane = 16.04 g/mol
Number of moles of methane = Mass of methane / Molar mass of methane
Number of moles of methane = 12.50 g / 16.04 g/mol
Calculating this, we find:
Number of moles of methane = 0.7783105022831050228310502283105 mol
Rounding to the correct number of significant figures, the answer is:
Number of moles of methane = 0.778 mol