Propane (C3H8, molar mass=44.09g/mol) can be prepared by the reaction of propene C3H6 molar mass=42.08 g/mol) with hydrogen (H2, molar mass=2.016 g/mol) according to the following balanced equation: C3H6+H2 C3H8
Assuming18.50g of propene and 28.50 of hydrogen are used, answer the following questions:
How many moles of propene are used? Be sure your answer has the correct number of significant figures.
How many moles of propane are formed? Be sure your answer has the correct number of significant figures.
To calculate the number of moles of propene used, we can use the formula:
moles = mass / molar mass
Using the given values:
mass = 18.50 g
molar mass of propene (C3H6) = 42.08 g/mol
moles of propene = 18.50 g / 42.08 g/mol
moles of propene ≈ 0.4396 mol
To calculate the number of moles of propane formed, we need to use the balanced equation, which states that 1 mole of propene reacts to form 1 mole of propane.
Therefore, the number of moles of propane formed is also approximately 0.4396 mol.