Maria wanted to bring back 5 million grains of sand from her trip to the beach. Each grain of sand weighs approximately 6.7×10−7%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A kg. How heavy is the bag of sand that Maria brings home?(1 point)%0D%0AResponses%0D%0A%0D%0AMultiply 5,000,000(6.7×10−7)=(5×106)⋅(6.7×10−7)=(5⋅6.7)(106+(−7))=33.5×10−1=3.35%0D%0A5%0D%0A,%0D%0A000%0D%0A,%0D%0A000%0D%0A(%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A)%0D%0A=%0D%0A(%0D%0A5%0D%0A×%0D%0A10%0D%0A6%0D%0A)%0D%0A⋅%0D%0A(%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A)%0D%0A=%0D%0A(%0D%0A5%0D%0A⋅%0D%0A6.7%0D%0A)%0D%0A(%0D%0A10%0D%0A6%0D%0A+%0D%0A(%0D%0A−%0D%0A7%0D%0A)%0D%0A)%0D%0A=%0D%0A33.5%0D%0A×%0D%0A10%0D%0A−%0D%0A1%0D%0A=%0D%0A3.35%0D%0A kg%0D%0AMultiply 5 comma 000 comma 000 times open paren 6 point 7 times 10 to the negative 7 power close paren is equal to open paren 5 times 10 to the 6th power close paren times open paren 6 point 7 times 10 to the negative 7 power close paren is equal to open paren 5 times 6 point 7 close paren times open paren 10 raised to the 6 plus negative 7 power close paren is equal to 33 point 5 times 10 inverse is equal to 3 point 3 5 kg%0D%0A%0D%0ADivide 5,000,0006.7×10−7=5×1066.7×10−7=(56.7)×106+(−7)=0.74×10−1=0.074%0D%0A5%0D%0A,%0D%0A000%0D%0A,%0D%0A000%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A=%0D%0A5%0D%0A×%0D%0A10%0D%0A6%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A=%0D%0A(%0D%0A5%0D%0A6.7%0D%0A)%0D%0A×%0D%0A10%0D%0A6%0D%0A+%0D%0A(%0D%0A−%0D%0A7%0D%0A)%0D%0A=%0D%0A0.74%0D%0A×%0D%0A10%0D%0A−%0D%0A1%0D%0A=%0D%0A0.074%0D%0A kg%0D%0ADivide the fraction with numerator 5 comma 000 comma 000 and denominator 6 point 7 times 10 to the negative 7 power is equal to the fraction with numerator 5 times 10 to the 6th power and denominator 6 point 7 times 10 to the negative 7 power is equal to open paren 5 over 6 point 7 close paren times 10 raised to the 6 plus negative 7 power is equal to 0 point 7 4 times 10 inverse is equal to 0 point 0 7 4 kg%0D%0A%0D%0AMultiply 5(6.7×10−7) = 33.5×10−7=3.35×10−6%0D%0A5%0D%0A(%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A)%0D%0A %0D%0A=%0D%0A %0D%0A33.5%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A=%0D%0A3.35%0D%0A×%0D%0A10%0D%0A−%0D%0A6%0D%0A kg%0D%0AMultiply 5(6.7×10−7) = 33.5×10−7=3.35×10−6%0D%0A5%0D%0A(%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A)%0D%0A %0D%0A=%0D%0A %0D%0A33.5%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A=%0D%0A3.35%0D%0A×%0D%0A10%0D%0A−%0D%0A6%0D%0A kg%0D%0A%0D%0AMultiply 5,000,000(6.7×10−7)=(5×106)⋅(6.7×10−7)=(5⋅6.7)(106+7)=33.5×1013=3.35×1014%0D%0A5%0D%0A,%0D%0A000%0D%0A,%0D%0A000%0D%0A(%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A)%0D%0A=%0D%0A(%0D%0A5%0D%0A×%0D%0A10%0D%0A6%0D%0A)%0D%0A⋅%0D%0A(%0D%0A6.7%0D%0A×%0D%0A10%0D%0A−%0D%0A7%0D%0A)%0D%0A=%0D%0A(%0D%0A5%0D%0A⋅%0D%0A6.7%0D%0A)%0D%0A(%0D%0A10%0D%0A6%0D%0A+%0D%0A7%0D%0A)%0D%0A=%0D%0A33.5%0D%0A×%0D%0A10%0D%0A13%0D%0A=%0D%0A3.35%0D%0A×%0D%0A10%0D%0A14%0D%0A kg
