How many atoms of MgO are present in 13.0 moles?
Responses
7.8 x 1024 atoms
7.8 x 10 24 atoms
78 atoms
78 atoms
4.6 x 1022 atoms
4.6 x 10 22 atoms
0.46 atoms
To determine the number of atoms of MgO present in 13.0 moles, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms or molecules).
MgO has a 1:1 ratio of Mg to O atoms, so for every one mole of MgO, there is an equal number of moles of Mg and O atoms.
Therefore, the number of atoms of MgO in 13.0 moles is calculated as follows:
Number of moles of MgO = 13.0 moles
Number of atoms of MgO = 13.0 moles x (6.022 x 10^23 atoms/mole) = 7.8 x 10^24 atoms.
So the correct answer is:
7.8 x 10^24 atoms