Solve the following system by the substitution method.
4x−14=−y
3x−y=0
(1 point)
To solve the system by the substitution method, we will solve one equation for one variable and then substitute that expression into the other equation.
From the first equation, we can solve for y:
4x - 14 = -y
y = -4x + 14
Now we can substitute this expression for y into the second equation:
3x - (-4x + 14) = 0
3x + 4x - 14 = 0
7x - 14 = 0
7x = 14
x = 2
Now substitute this value of x back into the expression for y:
y = -4(2) + 14
y = 6
Therefore, the solution to the system is x = 2 and y = 6.