Find the number of real number solutions for the equation. x^2 - 10x + 25 = 0
The equation is a quadratic equation in the form of $ax^2 + bx + c = 0$ where $a = 1$, $b = -10$, and $c = 25$.
To find the number of real number solutions for the equation, we can use the discriminant which is given by $D = b^2 - 4ac$.
In this case, $D = (-10)^2 - 4(1)(25) = 100 - 100 = 0$.
Since the discriminant is zero, there is only one real number solution for the equation.