The area of a playground is 204 yd^2. The width of the playground is 5 yd longer than its length. Find the length and width of the playground.
Let the length of the playground be x.
The width of the playground is x + 5.
The area of the playground is x(x + 5) = 204 yd^2.
x^2 + 5x - 204 = 0.
(x + 17)(x - 12) = 0.
The possible solutions are x = -17 and x = 12.
Since the dimensions cannot be negative, the length of the playground is 12 yd and the width is 17 yd. Answer: \boxed{(12, 17)}