What is the number of moles in 423 g Ba(NO3)2
Responses
1.62 mol
1.62 mol
0.237 mol
0.237 mol
0.605 mol
0.605 mol
3.66 mol
To find the number of moles in 423 g of Ba(NO3)2, we need to convert the mass of the substance to moles using its molar mass.
The molar mass of Ba(NO3)2 can be calculated by adding up the atomic masses of each element:
Ba: 1 atom * 137.33 g/mol = 137.33 g/mol
N: 2 atoms * 14.01 g/mol = 28.02 g/mol
O: 6 atoms * 16.00 g/mol = 96.00 g/mol
Adding these up, we get:
Ba(NO3)2 molar mass = 137.33 g/mol + 28.02 g/mol + 96.00 g/mol = 261.35 g/mol
Now, we can use the formula:
Number of moles = Mass / Molar mass
Number of moles = 423 g / 261.35 g/mol ≈ 1.62 mol
Therefore, the number of moles in 423 g of Ba(NO3)2 is approximately 1.62 mol. The first response is correct.