Use the image to answer the question.
An illustration shows a polygon where the top, right, and bottom sides are perpendicular to each other. A smaller rectangular piece is missing from the center of the left side of the polygon inward. The dimensions are as follows: the top side is 6, the right side is 8, and the bottom side is 6. The left side is divided into three parts. It shows a vertical width of 2 from the top
Solve the following problem using what you know about composite figures. What is the area of the figure?
(1 point)
Responses
24 square units
24 square units
36 square units
36 square units
30 square units
30 square units
48 square units
To find the area of the figure, we can break it down into smaller shapes and then add up their areas.
The figure consists of a larger rectangle (with sides 6 and 8) and a smaller rectangular piece missing from the left side.
The area of the larger rectangle is 6 multiplied by 8, which equals 48.
Now, let's calculate the area of the missing rectangular piece. The width of the missing piece is given as 2 units. We need to find the length of the missing piece.
From the given information, we know that the top side of the larger rectangle is 6 units long, and the width of the missing piece at the top is 2 units. So, the remaining width on the left side is (6 - 2 = 4) units.
Therefore, the missing rectangular piece has a length of 4 units and a width of 2 units. The area of this missing piece is 4 multiplied by 2, which equals 8.
Now we can find the total area of the figure by subtracting the area of the missing piece from the area of the larger rectangle: 48 - 8 = 40.
Therefore, the area of the figure is 40 square units.
positive
Apologies for the error in my previous response.
To find the area of the figure, we can break it down into smaller shapes and then add up their areas.
The figure consists of a larger rectangle (with sides 6 and 8) and a smaller rectangular piece missing from the left side.
The area of the larger rectangle is 6 multiplied by 8, which equals 48.
Now, let's calculate the area of the missing rectangular piece. The width of the missing piece is given as 2 units. We need to find the length of the missing piece.
From the given information, we know that the top side of the larger rectangle is 6 units long, and the width of the missing piece at the top is 2 units. So, the remaining width on the left side is (6 - 2 = 4) units.
Therefore, the missing rectangular piece has a length of 4 units and a width of 2 units. The area of this missing piece is 4 multiplied by 2, which equals 8.
Now we can find the total area of the figure by subtracting the area of the missing piece from the area of the larger rectangle: 48 - 8 = 40.
Therefore, the area of the figure is 40 square units.
that is not an answer
Apologies for the confusion. Based on the given information and the image description, the area of the figure can be calculated as follows:
The larger rectangle has a length of 6 units and a width of 8 units, so the area of the larger rectangle is 6 * 8 = 48 square units.
The missing rectangular piece has a width of 2 units and is 4 units in length (the remaining length on the left side of the larger rectangle). Therefore, the area of the missing piece is 2 * 4 = 8 square units.
To find the total area of the figure, we subtract the area of the missing piece from the area of the larger rectangle: 48 - 8 = 40 square units.
Therefore, the area of the figure is 40 square units.