Lorna and Lupe are playing a ring toss game at the fair. The cost to play the game depends on the number of rings purchased. The cost is described in the piecewise function, where x is the number of rings purchased. Lorna and Lupe each want to purchase 5 rings. What is the difference in price if they each separately purchase 5 rings compared to making one purchase of 10 rings? Round the answer to the nearest cent.%0D%0A%0D%0Af(x)=⎧⎩⎨⎪⎪2x,1.5x,1.25x, 0≤x≤34≤x≤7x≥8
To find the price if they each separately purchase 5 rings, we can substitute x = 5 into the piecewise function:
f(5) = 2 * 5 = 10
So each ring costs $10 if they each separately purchase 5 rings.
To find the price if they make one purchase of 10 rings, we can substitute x = 10 into the piecewise function:
f(10) = 1.25 * 10 = 12.50
So each ring costs $12.50 if they make one purchase of 10 rings.
The difference in price is 12.50 - 10 = $2.50.
Therefore, the difference in price is $2.50.