Find the slope of a line perpendicular to the line whose equation is 3, x, minus, 2, y, equals, 63x−2y=6. Fully simplify your answer
First, let's put the given equation in slope-intercept form (y = mx + b):
63x - 2y = 6
-2y = -63x + 6
y = (63/2)x - 3
The slope of the line is the coefficient of x, which in this case is 63/2.
To find the slope of a line perpendicular to this line, we flip the fraction and change its sign:
Perpendicular slope = -2/63
Therefore, the slope of a line perpendicular to the given line is -2/63.