Nan’s suitcase is on a bench. The suitcase has a mass of 14 kilograms. Nan accidentally knocks the suitcase off the bench, and the suitcase falls at a speed of 2.7 meters per second. How much kinetic energy does the suitcase have just before it hits the floor?
KE= 1/2 mv^2
(1 point)
Responses
51.03 J
51.03 J
204.12 J
204.12 J
18.9 J
18.9 J
102.06 J
To find the kinetic energy (KE) of the suitcase just before it hits the floor, we can use the formula KE = 1/2 * m * v^2, where m is the mass of the suitcase and v is its velocity.
Plugging in the values:
m = 14 kg
v = 2.7 m/s
KE = 1/2 * 14 kg * (2.7 m/s)^2
KE = 1/2 * 14 kg * 7.29 m^2/s^2
KE = 102.06 J
Therefore, the kinetic energy of the suitcase just before it hits the floor is 102.06 J.