A playground is on the flat roof of a city school, 7.00 m above the street below. The vertical wall of the building is 8.00 m high, forming a 1.00 m high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of 53.0° above the horizontal at a point 24.0 m from the base of the building wall. The ball takes 2.00 s to reach a point vertically above the wall.
I had solved for A, but I am unable to solve for B and C, it says that I was off by 10-100%.
(a) Find the speed at which the ball was launched. 19.9 m/s
(b) Find the vertical distance by which the ball clears the wall.
(c) Find the distance from the wall to the point on the roof where the ball lands.
Assuming a) is right.
b) how long does it take to get to the wall plane? time= 24/(19.9cosTheta)
Now using that time..
vertical height= 19.9sinTheta*t-1/2 g t^2
and clearance is that minus 8m
posted by bobpursley