What is the percent composition of H in C6H12O6 ?
To find the percent composition of hydrogen (H) in C6H12O6, we need to calculate the molar mass of hydrogen and the molar mass of the entire compound.
The molar mass of hydrogen (H) is approximately 1.008 g/mol.
The molar mass of C6H12O6 is calculated as follows:
(6 * molar mass of carbon) + (12 * molar mass of hydrogen) + (6 * molar mass of oxygen)
= (6 * 12.01 g/mol) + (12 * 1.008 g/mol) + (6 * 16.00 g/mol)
= 72.06 g/mol + 12.096 g/mol + 96.00 g/mol
= 180.156 g/mol
To calculate the percent composition of hydrogen in C6H12O6, we divide the molar mass of hydrogen by the molar mass of the entire compound and multiply by 100.
(12 * 1.008 g/mol / 180.156 g/mol) * 100 ≈ 6.713%
Therefore, the percent composition of hydrogen (H) in C6H12O6 is approximately 6.713%.