What is the percent composition of O in C6H12O6 ?
To find the percent composition of oxygen (O) in C6H12O6, we need to determine the molar mass of oxygen in C6H12O6 and divide it by the molar mass of C6H12O6.
The molar mass of oxygen (O) is 16.00 g/mol.
To find the molar mass of C6H12O6, we can calculate the sum of the atomic masses of carbon (C), hydrogen (H), and oxygen (O) in one molecule of C6H12O6.
The atomic mass of carbon (C) is 12.01 g/mol.
The atomic mass of hydrogen (H) is 1.01 g/mol.
Molar mass of C6H12O6 = 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol)
= 72.06 g/mol + 12.12 g/mol + 96.00 g/mol
= 180.18 g/mol
Now, we can calculate the percent composition of oxygen (O).
Percent composition of O in C6H12O6 = (16.00 g/mol / 180.18 g/mol) × 100%
= 8.88%
Therefore, the percent composition of oxygen (O) in C6H12O6 is approximately 8.88%.