A right triangle has a hypotneuse of x an adjacent of 9 and an oppisite of 15
Solve for x. Round to the nearest tenth. Please show all work including the trig function used in order to receive full credit.
In a right triangle, the hypotenuse, adjacent side, and opposite side are related using trigonometric functions.
We are given that the adjacent side is 9 and the opposite side is 15. To solve for the hypotenuse, we can use the Pythagorean theorem:
hypotenuse^2 = adjacent^2 + opposite^2
x^2 = 9^2 + 15^2
x^2 = 81 + 225
x^2 = 306
Now, to solve for x, we take the square root of both sides:
x = sqrt(306)
x ≈ 17.5
Therefore, the hypotenuse of the right triangle is approximately 17.5.