The amount of heat needed to raise 25 g of a substance by 15°C is 293 J.
What is the specific heat of the substance?
Use the equation C = q/mΔT .
Question 6 options:
0.13 J/g-°C
0.20 J/g-°C
0.46 J/g-°C
0.78 J/g-°C
To find the specific heat of the substance, we can rearrange the equation C = q/mΔT to solve for C:
C = q / (mΔT)
C = 293 J / (25 g * 15°C)
C = 293 J / (375 g*°C)
C = 0.78 J/g-°C
Therefore, the specific heat of the substance is 0.78 J/g-°C.