two pumps are filling large vats of liquid one vat is empty and the is filling it ata s reate of 6 gallons per minute
Assuming that the other vat is already full or has a steady level of liquid, we can focus on the empty vat being filled at a rate of 6 gallons per minute.
Let's say the empty vat can hold X gallons of liquid. After t minutes of filling, the vat will have 6t gallons of liquid. We need to find the time it would take to fill the vat completely.
If the vat is empty, it means it can hold 0 gallons of liquid. We set up the equation:
6t = X
Solving for t, we find:
t = X/6
Therefore, it would take X/6 minutes to completely fill the vat.