The cost of 6 cows are same as a cost of 8 goats if cost of 9 cows and twice numbered goats is 9000 the the cost of 3 cows and 6 goats is equal to
To solve this problem, let's assign variables to each unknown value. Let's call the cost of one cow "x" and the cost of one goat "y".
According to the information given, the cost of 6 cows is the same as the cost of 8 goats. So, we can write the equation:
6x = 8y
We are also given that the cost of 9 cows and twice the number of goats is 9000. So, we can write the equation:
9x + 2(8y) = 9000
Now, we need to find the cost of 3 cows and 6 goats. Let's call this cost "z". We can write the equation:
3x + 6y = z
To solve this system of equations, we can use substitution. We can first solve the equations 6x = 8y and 9x + 2(8y) = 9000 to find the values of x and y.
From the equation 6x = 8y, we can divide both sides by 2 to simplify the equation:
3x = 4y
Now we have two equations:
3x = 4y ----(1)
9x + 2(8y) = 9000 ----(2)
We can rewrite equation 2 as:
9x + 16y = 9000
Now, from equation (1), we can rewrite the equation as:
y = (3/4)x
Now, substitute this value of y in equation (2):
9x + 16((3/4)x) = 9000
9x + 12x = 9000
21x = 9000
x = 9000/21
x ≈ 428.57
Now, substitute the value of x back into equation (1) to find y:
3(428.57) = 4y
y ≈ 321.43
So, the cost of one cow is approximately 428.57 and the cost of one goat is approximately 321.43.
Finally, substitute these values into the equation z = 3x + 6y to find the cost of 3 cows and 6 goats:
z = 3(428.57) + 6(321.43)
z ≈ 1285.71 + 1928.58
z ≈ 3214.29
Therefore, the cost of 3 cows and 6 goats is approximately 3214.29.